Base | Representation |
---|---|
bin | 110000011101011010101… |
… | …011111001111010010000 |
3 | 102210100121212101101200121 |
4 | 300131122223321322100 |
5 | 414030042001110412 |
6 | 11025500404400024 |
7 | 462410335264204 |
oct | 60353253717220 |
9 | 12710555341617 |
10 | 3330121113232 |
11 | 1074329609191 |
12 | 4594969a6014 |
13 | 1b204bb4a424 |
14 | b72705acb04 |
15 | 5b9564a2107 |
hex | 3075aaf9e90 |
3330121113232 has 40 divisors (see below), whose sum is σ = 6518775698240. Its totient is φ = 1647876389760.
The previous prime is 3330121113223. The next prime is 3330121113239. The reversal of 3330121113232 is 2323111210333.
It is a super-3 number, since 3×33301211132323 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 3330121113197 and 3330121113206.
It is not an unprimeable number, because it can be changed into a prime (3330121113239) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2048119 + ... + 3294697.
It is an arithmetic number, because the mean of its divisors is an integer number (162969392456).
Almost surely, 23330121113232 is an apocalyptic number.
It is an amenable number.
3330121113232 is a deficient number, since it is larger than the sum of its proper divisors (3188654585008).
3330121113232 is a wasteful number, since it uses less digits than its factorization.
3330121113232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1248311 (or 1248305 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 3330121113232 its reverse (2323111210333), we get a palindrome (5653232323565).
The spelling of 3330121113232 in words is "three trillion, three hundred thirty billion, one hundred twenty-one million, one hundred thirteen thousand, two hundred thirty-two".
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