Base | Representation |
---|---|
bin | 11111000001000001… |
… | …010111101111000001 |
3 | 10011221221201110011212 |
4 | 133001001113233001 |
5 | 1021201100224441 |
6 | 23144345415505 |
7 | 2256165650366 |
oct | 370101275701 |
9 | 104857643155 |
10 | 33303133121 |
11 | 1313a828915 |
12 | 655519a595 |
13 | 31a980353b |
14 | 187cddc46d |
15 | cedae9eeb |
hex | 7c1057bc1 |
33303133121 has 2 divisors, whose sum is σ = 33303133122. Its totient is φ = 33303133120.
The previous prime is 33303133057. The next prime is 33303133151. The reversal of 33303133121 is 12133130333.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23851404721 + 9451728400 = 154439^2 + 97220^2 .
It is a cyclic number.
It is not a de Polignac number, because 33303133121 - 26 = 33303133057 is a prime.
It is a super-2 number, since 2×333031331212 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (33303133151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16651566560 + 16651566561.
It is an arithmetic number, because the mean of its divisors is an integer number (16651566561).
Almost surely, 233303133121 is an apocalyptic number.
It is an amenable number.
33303133121 is a deficient number, since it is larger than the sum of its proper divisors (1).
33303133121 is an equidigital number, since it uses as much as digits as its factorization.
33303133121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 33303133121 its reverse (12133130333), we get a palindrome (45436263454).
The spelling of 33303133121 in words is "thirty-three billion, three hundred three million, one hundred thirty-three thousand, one hundred twenty-one".
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