Base | Representation |
---|---|
bin | 110000011101100111101… |
… | …110111011110000011011 |
3 | 102210101012010021120000122 |
4 | 300131213232323300123 |
5 | 414031014020323120 |
6 | 11025534224223455 |
7 | 462415634010212 |
oct | 60354756736033 |
9 | 12711163246018 |
10 | 3330340011035 |
11 | 1074431129364 |
12 | 45953816ab8b |
13 | 1b20852c025b |
14 | b72916b0079 |
15 | 5b96a7e0a25 |
hex | 30767bbbc1b |
3330340011035 has 32 divisors (see below), whose sum is σ = 4089788902080. Its totient is φ = 2602604003328.
The previous prime is 3330340011001. The next prime is 3330340011041. The reversal of 3330340011035 is 5301100430333.
It is a cyclic number.
It is not a de Polignac number, because 3330340011035 - 214 = 3330339994651 is a prime.
It is a super-2 number, since 2×33303400110352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3330340010995 and 3330340011013.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 102921419 + ... + 102953771.
It is an arithmetic number, because the mean of its divisors is an integer number (127805903190).
Almost surely, 23330340011035 is an apocalyptic number.
3330340011035 is a deficient number, since it is larger than the sum of its proper divisors (759448891045).
3330340011035 is a wasteful number, since it uses less digits than its factorization.
3330340011035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34607.
The product of its (nonzero) digits is 4860, while the sum is 26.
Adding to 3330340011035 its reverse (5301100430333), we get a palindrome (8631440441368).
The spelling of 3330340011035 in words is "three trillion, three hundred thirty billion, three hundred forty million, eleven thousand, thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •