3330340011041 has 2 divisors, whose sum is σ = 3330340011042. Its totient is φ = 3330340011040.

The previous prime is 3330340011001. The next prime is 3330340011049. The reversal of 3330340011041 is 1401100430333.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2044828500625 + 1285511510416 = 1429975^2 + 1133804^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3330340011041 is a prime.

It is a super-2 number, since 2×3330340011041² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3330340010998 and 3330340011016.

It is not a weakly prime, because it can be changed into another prime (3330340011049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665170005520 + 1665170005521.

It is an arithmetic number, because the mean of its divisors is an integer number (1665170005521).

Almost surely, 2^{3330340011041} is an apocalyptic number.

It is an amenable number.

3330340011041 is a deficient number, since it is larger than the sum of its proper divisors (1).

3330340011041 is an equidigital number, since it uses as much as digits as its factorization.

3330340011041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 3330340011041 its reverse (1401100430333), we get a palindrome (4731440441374).

The spelling of 3330340011041 in words is "three trillion, three hundred thirty billion, three hundred forty million, eleven thousand, forty-one".