Base | Representation |
---|---|
bin | 11111000001001010… |
… | …000100000110100001 |
3 | 10011222010000020012211 |
4 | 133001022010012201 |
5 | 1021202141141001 |
6 | 23144510322121 |
7 | 2256224221351 |
oct | 370112040641 |
9 | 104863006184 |
10 | 33305412001 |
11 | 13141044a94 |
12 | 6555ab9341 |
13 | 31aa1208a4 |
14 | 187d432b61 |
15 | ceddea351 |
hex | 7c12841a1 |
33305412001 has 2 divisors, whose sum is σ = 33305412002. Its totient is φ = 33305412000.
The previous prime is 33305411983. The next prime is 33305412013. The reversal of 33305412001 is 10021450333.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31618174225 + 1687237776 = 177815^2 + 41076^2 .
It is a cyclic number.
It is not a de Polignac number, because 33305412001 - 27 = 33305411873 is a prime.
It is a super-2 number, since 2×333054120012 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (33305412071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16652706000 + 16652706001.
It is an arithmetic number, because the mean of its divisors is an integer number (16652706001).
Almost surely, 233305412001 is an apocalyptic number.
It is an amenable number.
33305412001 is a deficient number, since it is larger than the sum of its proper divisors (1).
33305412001 is an equidigital number, since it uses as much as digits as its factorization.
33305412001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1080, while the sum is 22.
Adding to 33305412001 its reverse (10021450333), we get a palindrome (43326862334).
The spelling of 33305412001 in words is "thirty-three billion, three hundred five million, four hundred twelve thousand, one".
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