Base | Representation |
---|---|
bin | 110000011110010000010… |
… | …101111011011100001001 |
3 | 102210102221121021201221211 |
4 | 300132100111323130021 |
5 | 414033412424300433 |
6 | 11030130003133121 |
7 | 462441546032431 |
oct | 60362025733411 |
9 | 12712847251854 |
10 | 3331021321993 |
11 | 1074750773372 |
12 | 4596a83741a1 |
13 | 1b21634b7b31 |
14 | b7317d812c1 |
15 | 5b9aa5208cd |
hex | 3079057b709 |
3331021321993 has 2 divisors, whose sum is σ = 3331021321994. Its totient is φ = 3331021321992.
The previous prime is 3331021321981. The next prime is 3331021322009. The reversal of 3331021321993 is 3991231201333.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3043583800569 + 287437521424 = 1744587^2 + 536132^2 .
It is a cyclic number.
It is not a de Polignac number, because 3331021321993 - 217 = 3331021190921 is a prime.
It is a super-2 number, since 2×33310213219932 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3331021321093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665510660996 + 1665510660997.
It is an arithmetic number, because the mean of its divisors is an integer number (1665510660997).
Almost surely, 23331021321993 is an apocalyptic number.
It is an amenable number.
3331021321993 is a deficient number, since it is larger than the sum of its proper divisors (1).
3331021321993 is an equidigital number, since it uses as much as digits as its factorization.
3331021321993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 78732, while the sum is 40.
The spelling of 3331021321993 in words is "three trillion, three hundred thirty-one billion, twenty-one million, three hundred twenty-one thousand, nine hundred ninety-three".
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