Base | Representation |
---|---|
bin | 1100011010001100… |
… | …1000110111100011 |
3 | 22121011001102022221 |
4 | 3012203020313203 |
5 | 23310230201011 |
6 | 1310313011511 |
7 | 145355612122 |
oct | 30643106743 |
9 | 8534042287 |
10 | 3331100131 |
11 | 145a356917 |
12 | 78b6b3b97 |
13 | 411180c88 |
14 | 238593ab9 |
15 | 147697971 |
hex | c68c8de3 |
3331100131 has 2 divisors, whose sum is σ = 3331100132. Its totient is φ = 3331100130.
The previous prime is 3331100117. The next prime is 3331100141. The reversal of 3331100131 is 1310011333.
3331100131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (1310011333) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3331100131 - 221 = 3329002979 is a prime.
It is a super-2 number, since 2×33311001312 = 22192456165496434322, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3331100141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665550065 + 1665550066.
It is an arithmetic number, because the mean of its divisors is an integer number (1665550066).
Almost surely, 23331100131 is an apocalyptic number.
3331100131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3331100131 is an equidigital number, since it uses as much as digits as its factorization.
3331100131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 16.
The square root of 3331100131 is about 57715.6835790758. The cubic root of 3331100131 is about 1493.4679115413.
Adding to 3331100131 its reverse (1310011333), we get a palindrome (4641111464).
The spelling of 3331100131 in words is "three billion, three hundred thirty-one million, one hundred thousand, one hundred thirty-one".
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