Base | Representation |
---|---|
bin | 110000011110010111000… |
… | …100100010010011011011 |
3 | 102210110020110200200201112 |
4 | 300132113010202103123 |
5 | 414034130323444344 |
6 | 11030145114410535 |
7 | 462444416354033 |
oct | 60362704422333 |
9 | 12713213620645 |
10 | 3331134203099 |
11 | 10747a946263a |
12 | 45971a130a4b |
13 | 1b21809bb6a1 |
14 | b7328d668c3 |
15 | 5b9b53bbc9e |
hex | 307971224db |
3331134203099 has 2 divisors, whose sum is σ = 3331134203100. Its totient is φ = 3331134203098.
The previous prime is 3331134203093. The next prime is 3331134203119. The reversal of 3331134203099 is 9903024311333.
It is a weak prime.
It is an emirp because it is prime and its reverse (9903024311333) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3331134203099 is a prime.
It is a super-2 number, since 2×33311342030992 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3331134203093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665567101549 + 1665567101550.
It is an arithmetic number, because the mean of its divisors is an integer number (1665567101550).
Almost surely, 23331134203099 is an apocalyptic number.
3331134203099 is a deficient number, since it is larger than the sum of its proper divisors (1).
3331134203099 is an equidigital number, since it uses as much as digits as its factorization.
3331134203099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 157464, while the sum is 41.
The spelling of 3331134203099 in words is "three trillion, three hundred thirty-one billion, one hundred thirty-four million, two hundred three thousand, ninety-nine".
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