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3331201001993 is a prime number
BaseRepresentation
bin110000011110011011000…
…011010110101000001001
3102210110102010101102120122
4300132123003112220021
5414034244424030433
611030155502233025
7462446160216014
oct60363303265011
912713363342518
103331201001993
111074833137637
12459738585775
131b21917a9167
14b7333b9437b
155b9bb1b4198
hex3079b0d6a09

3331201001993 has 2 divisors, whose sum is σ = 3331201001994. Its totient is φ = 3331201001992.

The previous prime is 3331201001977. The next prime is 3331201002061. The reversal of 3331201001993 is 3991001021333.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2266358626249 + 1064842375744 = 1505443^2 + 1031912^2 .

It is a cyclic number.

It is not a de Polignac number, because 3331201001993 - 24 = 3331201001977 is a prime.

It is a super-2 number, since 2×33312010019932 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3331201001903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665600500996 + 1665600500997.

It is an arithmetic number, because the mean of its divisors is an integer number (1665600500997).

Almost surely, 23331201001993 is an apocalyptic number.

It is an amenable number.

3331201001993 is a deficient number, since it is larger than the sum of its proper divisors (1).

3331201001993 is an equidigital number, since it uses as much as digits as its factorization.

3331201001993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13122, while the sum is 35.

The spelling of 3331201001993 in words is "three trillion, three hundred thirty-one billion, two hundred one million, one thousand, nine hundred ninety-three".