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33312240012034 = 216656120006017
BaseRepresentation
bin1111001001100000111000…
…01110111000101100000010
311100221121201021122002122101
413210300130032320230002
513331241431420341114
6154503233133501014
710005505235065144
oct744603416705402
9140847637562571
1033312240012034
11a683707047255
1238a017594176a
13157843b888a09
1483246cc3cc94
153cb7db55bd74
hex1e4c1c3b8b02

33312240012034 has 4 divisors (see below), whose sum is σ = 49968360018054. Its totient is φ = 16656120006016.

The previous prime is 33312240011971. The next prime is 33312240012041. The reversal of 33312240012034 is 43021004221333.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 30554969799025 + 2757270213009 = 5527655^2 + 1660503^2 .

It is a super-3 number, since 3×333122400120343 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 33312240011993 and 33312240012011.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8328060003007 + ... + 8328060003010.

Almost surely, 233312240012034 is an apocalyptic number.

33312240012034 is a deficient number, since it is larger than the sum of its proper divisors (16656120006020).

33312240012034 is a wasteful number, since it uses less digits than its factorization.

33312240012034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16656120006019.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 33312240012034 its reverse (43021004221333), we get a palindrome (76333244233367).

The spelling of 33312240012034 in words is "thirty-three trillion, three hundred twelve billion, two hundred forty million, twelve thousand, thirty-four".

Divisors: 1 2 16656120006017 33312240012034