Base | Representation |
---|---|
bin | 110000011110100001101… |
… | …011111100000100100101 |
3 | 102210110200212211011210210 |
4 | 300132201223330010211 |
5 | 414040011422220141 |
6 | 11030214520010033 |
7 | 462452011243623 |
oct | 60364153740445 |
9 | 12713625734723 |
10 | 3331312304421 |
11 | 107488aa48812 |
12 | 459769900919 |
13 | 1b21ab87929a |
14 | b7344888513 |
15 | 5b9c5d4c916 |
hex | 307a1afc125 |
3331312304421 has 16 divisors (see below), whose sum is σ = 4486546228736. Its totient is φ = 2198492708976.
The previous prime is 3331312304413. The next prime is 3331312304477. The reversal of 3331312304421 is 1244032131333.
It is not a de Polignac number, because 3331312304421 - 23 = 3331312304413 is a prime.
It is a super-2 number, since 2×33313123044212 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3331312304401) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1180075 + ... + 2838168.
It is an arithmetic number, because the mean of its divisors is an integer number (280409139296).
Almost surely, 23331312304421 is an apocalyptic number.
It is an amenable number.
3331312304421 is a deficient number, since it is larger than the sum of its proper divisors (1155233924315).
3331312304421 is a wasteful number, since it uses less digits than its factorization.
3331312304421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4021032.
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 3331312304421 its reverse (1244032131333), we get a palindrome (4575344435754).
The spelling of 3331312304421 in words is "three trillion, three hundred thirty-one billion, three hundred twelve million, three hundred four thousand, four hundred twenty-one".
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