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33314000404 = 228328500101
BaseRepresentation
bin11111000001101010…
…110100111000010100
310011222201011120021211
4133001222310320110
51021211341003104
623145414351204
72256360221416
oct370152647024
9104881146254
1033314000404
1113145980643
12655895b504
1331abb39a99
14188062a9b6
15ceea44e04
hex7c1ab4e14

33314000404 has 6 divisors (see below), whose sum is σ = 58299500714. Its totient is φ = 16657000200.

The previous prime is 33314000399. The next prime is 33314000413. The reversal of 33314000404 is 40400041333.

It can be written as a sum of positive squares in only one way, i.e., 32504484100 + 809516304 = 180290^2 + 28452^2 .

It is a super-2 number, since 2×333140004042 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4164250047 + ... + 4164250054.

Almost surely, 233314000404 is an apocalyptic number.

It is an amenable number.

33314000404 is a deficient number, since it is larger than the sum of its proper divisors (24985500310).

33314000404 is a wasteful number, since it uses less digits than its factorization.

33314000404 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8328500105 (or 8328500103 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 22.

Adding to 33314000404 its reverse (40400041333), we get a palindrome (73714041737).

The spelling of 33314000404 in words is "thirty-three billion, three hundred fourteen million, four hundred four", and thus it is an aban number.

Divisors: 1 2 4 8328500101 16657000202 33314000404