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3332000114 = 21666000057
BaseRepresentation
bin1100011010011010…
…0100100101110010
322121012202010212122
43012212210211302
523310443000424
61310344154242
7145366351022
oct30646444562
98535663778
103332000114
11145a911003
1278ba68982
13411407801
14238749a82
151477c445e
hexc69a4972

3332000114 has 4 divisors (see below), whose sum is σ = 4998000174. Its totient is φ = 1666000056.

The previous prime is 3332000099. The next prime is 3332000123. The reversal of 3332000114 is 4110002333.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 2858720089 + 473280025 = 53467^2 + 21755^2 .

It is a super-2 number, since 2×33320001142 = 22204449519392025992, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3332000092 and 3332000101.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 833000027 + ... + 833000030.

Almost surely, 23332000114 is an apocalyptic number.

3332000114 is a deficient number, since it is larger than the sum of its proper divisors (1666000060).

3332000114 is a wasteful number, since it uses less digits than its factorization.

3332000114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1666000059.

The product of its (nonzero) digits is 216, while the sum is 17.

The square root of 3332000114 is about 57723.4797461137. The cubic root of 3332000114 is about 1493.6023991129.

Adding to 3332000114 its reverse (4110002333), we get a palindrome (7442002447).

The spelling of 3332000114 in words is "three billion, three hundred thirty-two million, one hundred fourteen", and thus it is an aban number.

Divisors: 1 2 1666000057 3332000114