Base | Representation |
---|---|
bin | 1100011010011010… |
… | …0100101010010001 |
3 | 22121012202011021021 |
4 | 3012212210222101 |
5 | 23310443003101 |
6 | 1310344155441 |
7 | 145366351612 |
oct | 30646445221 |
9 | 8535664237 |
10 | 3332000401 |
11 | 145a911244 |
12 | 78ba68b81 |
13 | 411407992 |
14 | 238749c09 |
15 | 1477c45a1 |
hex | c69a4a91 |
3332000401 has 2 divisors, whose sum is σ = 3332000402. Its totient is φ = 3332000400.
The previous prime is 3332000387. The next prime is 3332000407. The reversal of 3332000401 is 1040002333.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3234879376 + 97121025 = 56876^2 + 9855^2 .
It is an emirp because it is prime and its reverse (1040002333) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3332000401 - 217 = 3331869329 is a prime.
It is a super-2 number, since 2×33320004012 = 22204453344528321602, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3332000407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1666000200 + 1666000201.
It is an arithmetic number, because the mean of its divisors is an integer number (1666000201).
Almost surely, 23332000401 is an apocalyptic number.
It is an amenable number.
3332000401 is a deficient number, since it is larger than the sum of its proper divisors (1).
3332000401 is an equidigital number, since it uses as much as digits as its factorization.
3332000401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 16.
The square root of 3332000401 is about 57723.4822321038. The cubic root of 3332000401 is about 1493.6024419965.
Adding to 3332000401 its reverse (1040002333), we get a palindrome (4372002734).
The spelling of 3332000401 in words is "three billion, three hundred thirty-two million, four hundred one", and thus it is an aban number.
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