3332120401231 has 4 divisors (see below), whose sum is σ = 3334642825264. Its totient is φ = 3329597977200.

The previous prime is 3332120401213. The next prime is 3332120401237. The reversal of 3332120401231 is 1321040212333.

3332120401231 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3332120401231 - 2¹⁵ = 3332120368463 is a prime.

It is a super-2 number, since 2×3332120401231² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3332120401196 and 3332120401205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3332120401237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1261210035 + ... + 1261212676.

It is an arithmetic number, because the mean of its divisors is an integer number (833660706316).

Almost surely, 2^{3332120401231} is an apocalyptic number.

3332120401231 is a deficient number, since it is larger than the sum of its proper divisors (2522424033).

3332120401231 is a wasteful number, since it uses less digits than its factorization.

3332120401231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2522424032.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 3332120401231 its reverse (1321040212333), we get a palindrome (4653160613564).

The spelling of 3332120401231 in words is "three trillion, three hundred thirty-two billion, one hundred twenty million, four hundred one thousand, two hundred thirty-one".