33325104541041 has 24 divisors (see below), whose sum is σ = 49849152409056. Its totient is φ = 21438621449280.

The previous prime is 33325104540979. The next prime is 33325104541061. The reversal of 33325104541041 is 14014540152333.

33325104541041 is a `hidden beast` number, since 3 + 3 + 3 + 2 + 5 + 104 + 541 + 0 + 4 + 1 = 666.

It is not a de Polignac number, because 33325104541041 - 2⁶ = 33325104540977 is a prime.

It is a super-2 number, since 2×33325104541041² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 33325104540987 and 33325104541005.

It is not an unprimeable number, because it can be changed into a prime (33325104541061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 518711140 + ... + 518775381.

It is an arithmetic number, because the mean of its divisors is an integer number (2077048017044).

Almost surely, 2^{33325104541041} is an apocalyptic number.

It is an amenable number.

33325104541041 is a deficient number, since it is larger than the sum of its proper divisors (16524047868015).

33325104541041 is a wasteful number, since it uses less digits than its factorization.

33325104541041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1037486653 (or 1037486650 counting only the distinct ones).

The product of its (nonzero) digits is 86400, while the sum is 36.

Adding to 33325104541041 its reverse (14014540152333), we get a palindrome (47339644693374).

The spelling of 33325104541041 in words is "thirty-three trillion, three hundred twenty-five billion, one hundred four million, five hundred forty-one thousand, forty-one".