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33340013045142 = 239475867654531
BaseRepresentation
bin1111001010010100100111…
…01000100110010110010110
311101001021101211111100202020
413211022103220212112112
513332220321314421032
6154524105054154010
710010510414011146
oct745122350462626
9141037354440666
1033340013045142
11a694469212081
1238a5626ab2906
13157ac46769c0b
148339455ca926
153cc3b48ddb2c
hex1e5293a26596

33340013045142 has 16 divisors (see below), whose sum is σ = 66750437956032. Its totient is φ = 11101602370760.

The previous prime is 33340013045107. The next prime is 33340013045147. The reversal of 33340013045142 is 24154031004333.

It is a super-2 number, since 2×333400130451422 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (33340013045147) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2933821584 + ... + 2933832947.

It is an arithmetic number, because the mean of its divisors is an integer number (4171902372252).

Almost surely, 233340013045142 is an apocalyptic number.

33340013045142 is an abundant number, since it is smaller than the sum of its proper divisors (33410424910890).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

33340013045142 is a wasteful number, since it uses less digits than its factorization.

33340013045142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5867655483.

The product of its (nonzero) digits is 51840, while the sum is 33.

Adding to 33340013045142 its reverse (24154031004333), we get a palindrome (57494044049475).

The spelling of 33340013045142 in words is "thirty-three trillion, three hundred forty billion, thirteen million, forty-five thousand, one hundred forty-two".

Divisors: 1 2 3 6 947 1894 2841 5682 5867654531 11735309062 17602963593 35205927186 5556668840857 11113337681714 16670006522571 33340013045142