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33340033121 is a prime number
BaseRepresentation
bin11111000011001110…
…001000100001100001
310012001112011011110112
4133003032020201201
51021240022024441
623152144341105
72260124414513
oct370316104141
9105045134415
1033340033121
111315964138a
126565614795
1331b4353065
141883c85bb3
15d01e884eb
hex7c3388861

33340033121 has 2 divisors, whose sum is σ = 33340033122. Its totient is φ = 33340033120.

The previous prime is 33340033079. The next prime is 33340033127. The reversal of 33340033121 is 12133004333.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 24661247521 + 8678785600 = 157039^2 + 93160^2 .

It is a cyclic number.

It is not a de Polignac number, because 33340033121 - 210 = 33340032097 is a prime.

It is a super-2 number, since 2×333400331212 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (33340033127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16670016560 + 16670016561.

It is an arithmetic number, because the mean of its divisors is an integer number (16670016561).

Almost surely, 233340033121 is an apocalyptic number.

It is an amenable number.

33340033121 is a deficient number, since it is larger than the sum of its proper divisors (1).

33340033121 is an equidigital number, since it uses as much as digits as its factorization.

33340033121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 23.

Adding to 33340033121 its reverse (12133004333), we get a palindrome (45473037454).

The spelling of 33340033121 in words is "thirty-three billion, three hundred forty million, thirty-three thousand, one hundred twenty-one".