Base | Representation |
---|---|
bin | 1100011010111110… |
… | …0000000111101001 |
3 | 22121101011002002201 |
4 | 3012233200013221 |
5 | 23312042403342 |
6 | 1310510300201 |
7 | 145425301033 |
oct | 30657400751 |
9 | 8541132081 |
10 | 3334341097 |
11 | 146116a8aa |
12 | 7907b7661 |
13 | 411a471c9 |
14 | 238b98c53 |
15 | 147ad7db7 |
hex | c6be01e9 |
3334341097 has 2 divisors, whose sum is σ = 3334341098. Its totient is φ = 3334341096.
The previous prime is 3334341083. The next prime is 3334341133. The reversal of 3334341097 is 7901434333.
3334341097 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2866959936 + 467381161 = 53544^2 + 21619^2 .
It is a cyclic number.
It is not a de Polignac number, because 3334341097 - 231 = 1186857449 is a prime.
It is a super-2 number, since 2×33343410972 = 22235661102286326818, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3334341047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1667170548 + 1667170549.
It is an arithmetic number, because the mean of its divisors is an integer number (1667170549).
Almost surely, 23334341097 is an apocalyptic number.
It is an amenable number.
3334341097 is a deficient number, since it is larger than the sum of its proper divisors (1).
3334341097 is an equidigital number, since it uses as much as digits as its factorization.
3334341097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81648, while the sum is 37.
The square root of 3334341097 is about 57743.7537487822. The cubic root of 3334341097 is about 1493.9521069134.
The spelling of 3334341097 in words is "three billion, three hundred thirty-four million, three hundred forty-one thousand, ninety-seven".
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