Base | Representation |
---|---|
bin | 110000100110101000010… |
… | …101010111000010011011 |
3 | 102211022011022010221210001 |
4 | 300212220111113002123 |
5 | 414210322010320132 |
6 | 11034214154233431 |
7 | 463210440352003 |
oct | 60465025270233 |
9 | 12738138127701 |
10 | 3340013760667 |
11 | 107854576a671 |
12 | 45b397a25877 |
13 | 1b2c6751b56c |
14 | b792c389003 |
15 | 5bd34c06ce7 |
hex | 309a855709b |
3340013760667 has 2 divisors, whose sum is σ = 3340013760668. Its totient is φ = 3340013760666.
The previous prime is 3340013760659. The next prime is 3340013760673. The reversal of 3340013760667 is 7660673100433.
3340013760667 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3340013760667 - 23 = 3340013760659 is a prime.
It is a super-2 number, since 2×33400137606672 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3340013760647) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670006880333 + 1670006880334.
It is an arithmetic number, because the mean of its divisors is an integer number (1670006880334).
Almost surely, 23340013760667 is an apocalyptic number.
3340013760667 is a deficient number, since it is larger than the sum of its proper divisors (1).
3340013760667 is an equidigital number, since it uses as much as digits as its factorization.
3340013760667 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1143072, while the sum is 46.
The spelling of 3340013760667 in words is "three trillion, three hundred forty billion, thirteen million, seven hundred sixty thousand, six hundred sixty-seven".
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