3340042333 has 4 divisors (see below), whose sum is σ = 3396653280. Its totient is φ = 3283431388.

The previous prime is 3340042273. The next prime is 3340042337. The reversal of 3340042333 is 3332400433.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3340042333 - 2¹⁷ = 3339911261 is a prime.

It is a super-2 number, since 2×3340042333² = 22311765572464165778, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3340042298 and 3340042307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3340042337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28305385 + ... + 28305502.

It is an arithmetic number, because the mean of its divisors is an integer number (849163320).

Almost surely, 2^3340042333 is an apocalyptic number.

It is an amenable number.

3340042333 is a deficient number, since it is larger than the sum of its proper divisors (56610947).

3340042333 is an equidigital number, since it uses as much as digits as its factorization.

3340042333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56610946.

The product of its (nonzero) digits is 7776, while the sum is 25.

The square root of 3340042333 is about 57793.0993545077. The cubic root of 3340042333 is about 1494.8031019980.

Adding to 3340042333 its reverse (3332400433), we get a palindrome (6672442766).

The spelling of 3340042333 in words is "three billion, three hundred forty million, forty-two thousand, three hundred thirty-three".