Base | Representation |
---|---|
bin | 1100011100011001… |
… | …0111000001000001 |
3 | 22121210102111121112 |
4 | 3013012113001001 |
5 | 23320111124441 |
6 | 1311242533105 |
7 | 145530235346 |
oct | 30706270101 |
9 | 8553374545 |
10 | 3340333121 |
11 | 1464592794 |
12 | 792807195 |
13 | 413064698 |
14 | 2398b87cd |
15 | 1483bd4eb |
hex | c7197041 |
3340333121 has 2 divisors, whose sum is σ = 3340333122. Its totient is φ = 3340333120.
The previous prime is 3340333081. The next prime is 3340333127. The reversal of 3340333121 is 1213330433.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3336333121 + 4000000 = 57761^2 + 2000^2 .
It is a cyclic number.
It is not a de Polignac number, because 3340333121 - 214 = 3340316737 is a prime.
It is a super-2 number, since 2×33403331212 = 22315650718499201282, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3340333127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670166560 + 1670166561.
It is an arithmetic number, because the mean of its divisors is an integer number (1670166561).
Almost surely, 23340333121 is an apocalyptic number.
It is an amenable number.
3340333121 is a deficient number, since it is larger than the sum of its proper divisors (1).
3340333121 is an equidigital number, since it uses as much as digits as its factorization.
3340333121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 23.
The square root of 3340333121 is about 57795.6150672350. The cubic root of 3340333121 is about 1494.8464805092.
Adding to 3340333121 its reverse (1213330433), we get a palindrome (4553663554).
The spelling of 3340333121 in words is "three billion, three hundred forty million, three hundred thirty-three thousand, one hundred twenty-one".
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