334033314113 has 2 divisors, whose sum is σ = 334033314114. Its totient is φ = 334033314112.

The previous prime is 334033314091. The next prime is 334033314191. The reversal of 334033314113 is 311413330433.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 272334728449 + 61698585664 = 521857^2 + 248392^2 .

It is an emirp because it is prime and its reverse (311413330433) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-334033314113 is a prime.

It is a super-2 number, since 2×334033314113² (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (334033314413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167016657056 + 167016657057.

It is an arithmetic number, because the mean of its divisors is an integer number (167016657057).

Almost surely, 2^334033314113 is an apocalyptic number.

It is an amenable number.

334033314113 is a deficient number, since it is larger than the sum of its proper divisors (1).

334033314113 is an equidigital number, since it uses as much as digits as its factorization.

334033314113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11664, while the sum is 29.

Adding to 334033314113 its reverse (311413330433), we get a palindrome (645446644546).

The spelling of 334033314113 in words is "three hundred thirty-four billion, thirty-three million, three hundred fourteen thousand, one hundred thirteen".