33404144023141 has 4 divisors (see below), whose sum is σ = 33415935111052. Its totient is φ = 33392352935232.

The previous prime is 33404144023097. The next prime is 33404144023171. The reversal of 33404144023141 is 14132044140433.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6064275630625 + 27339868392516 = 2462575^2 + 5228754^2 .

It is a cyclic number.

It is not a de Polignac number, because 33404144023141 - 2²¹ = 33404141925989 is a prime.

It is a super-2 number, since 2×33404144023141² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 33404144023097 and 33404144023106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (33404144023171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5895539706 + ... + 5895545371.

It is an arithmetic number, because the mean of its divisors is an integer number (8353983777763).

Almost surely, 2^{33404144023141} is an apocalyptic number.

It is an amenable number.

33404144023141 is a deficient number, since it is larger than the sum of its proper divisors (11791087911).

33404144023141 is a wasteful number, since it uses less digits than its factorization.

33404144023141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11791087910.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 33404144023141 its reverse (14132044140433), we get a palindrome (47536188163574).

The spelling of 33404144023141 in words is "thirty-three trillion, four hundred four billion, one hundred forty-four million, twenty-three thousand, one hundred forty-one".