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334049167393 is a prime number
BaseRepresentation
bin1001101110001101110…
…00011100100000100001
31011221020110102221112221
410313012320130200201
520433113041324033
6413243212551041
733064023034054
oct4670670344041
91157213387487
10334049167393
11119740056767
12548a8482481
132566806b836
141224d25ca9b
158a51a2112d
hex4dc6e1c821

334049167393 has 2 divisors, whose sum is σ = 334049167394. Its totient is φ = 334049167392.

The previous prime is 334049167327. The next prime is 334049167409. The reversal of 334049167393 is 393761940433.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 313161113664 + 20888053729 = 559608^2 + 144527^2 .

It is a cyclic number.

It is not a de Polignac number, because 334049167393 - 221 = 334047070241 is a prime.

It is a super-2 number, since 2×3340491673932 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 334049167393.

It is not a weakly prime, because it can be changed into another prime (334049165393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167024583696 + 167024583697.

It is an arithmetic number, because the mean of its divisors is an integer number (167024583697).

Almost surely, 2334049167393 is an apocalyptic number.

It is an amenable number.

334049167393 is a deficient number, since it is larger than the sum of its proper divisors (1).

334049167393 is an equidigital number, since it uses as much as digits as its factorization.

334049167393 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4408992, while the sum is 52.

The spelling of 334049167393 in words is "three hundred thirty-four billion, forty-nine million, one hundred sixty-seven thousand, three hundred ninety-three".