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334120133055 = 3522274675537
BaseRepresentation
bin1001101110010110001…
…11001010000110111111
31011221102101222101010210
410313023013022012333
520433234223224210
6413254230003503
733065544162042
oct4671307120677
91157371871123
10334120133055
11119777117275
12549081a6593
1325679987a57
1412258852c59
158a57d8ce20
hex4dcb1ca1bf

334120133055 has 8 divisors (see below), whose sum is σ = 534592212912. Its totient is φ = 178197404288.

The previous prime is 334120133027. The next prime is 334120133131. The reversal of 334120133055 is 550331021433.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 334120133055 - 25 = 334120133023 is a prime.

It is a super-2 number, since 2×3341201330552 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11137337754 + ... + 11137337783.

It is an arithmetic number, because the mean of its divisors is an integer number (66824026614).

Almost surely, 2334120133055 is an apocalyptic number.

334120133055 is a deficient number, since it is larger than the sum of its proper divisors (200472079857).

334120133055 is a wasteful number, since it uses less digits than its factorization.

334120133055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22274675545.

The product of its (nonzero) digits is 16200, while the sum is 30.

Adding to 334120133055 its reverse (550331021433), we get a palindrome (884451154488).

The spelling of 334120133055 in words is "three hundred thirty-four billion, one hundred twenty million, one hundred thirty-three thousand, fifty-five".

Divisors: 1 3 5 15 22274675537 66824026611 111373377685 334120133055