Base | Representation |
---|---|
bin | 100101111111000011111000… |
… | …0001110001010011101001011 |
3 | 1121211000210101000020101220111 |
4 | 1023332013300032022131023 |
5 | 322243230204300234121 |
6 | 3142341415442335151 |
7 | 130243356033321424 |
oct | 11376076016123513 |
9 | 1554023330211814 |
10 | 334122421102411 |
11 | 97509583182347 |
12 | 315831b695a4b7 |
13 | 114587bc2c0916 |
14 | 5c7187bc1c64b |
15 | 2896456ddc2e1 |
hex | 12fe1f038a74b |
334122421102411 has 2 divisors, whose sum is σ = 334122421102412. Its totient is φ = 334122421102410.
The previous prime is 334122421102387. The next prime is 334122421102451. The reversal of 334122421102411 is 114201124221433.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 334122421102411 - 231 = 334120273618763 is a prime.
It is a super-2 number, since 2×3341224211024112 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (334122421102451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167061210551205 + 167061210551206.
It is an arithmetic number, because the mean of its divisors is an integer number (167061210551206).
Almost surely, 2334122421102411 is an apocalyptic number.
334122421102411 is a deficient number, since it is larger than the sum of its proper divisors (1).
334122421102411 is an equidigital number, since it uses as much as digits as its factorization.
334122421102411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 334122421102411 its reverse (114201124221433), we get a palindrome (448323545323844).
The spelling of 334122421102411 in words is "three hundred thirty-four trillion, one hundred twenty-two billion, four hundred twenty-one million, one hundred two thousand, four hundred eleven".
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