Base | Representation |
---|---|
bin | 100101111111000111111011… |
… | …1111011010100000000100010 |
3 | 1121211001121212122222012102112 |
4 | 1023332033313323110000202 |
5 | 322243401033410004442 |
6 | 3142345420553315322 |
7 | 130244115066354005 |
oct | 11376176773240042 |
9 | 1554047778865375 |
10 | 334131140313122 |
11 | 97512247a20409 |
12 | 31584a2aa05b42 |
13 | 1145957b83b1b9 |
14 | 5c72067c2153c |
15 | 28967b7602082 |
hex | 12fe3f7ed4022 |
334131140313122 has 4 divisors (see below), whose sum is σ = 501196710469686. Its totient is φ = 167065570156560.
The previous prime is 334131140313107. The next prime is 334131140313169. The reversal of 334131140313122 is 221313041131433.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 302088419637481 + 32042720675641 = 17380691^2 + 5660629^2 .
It is a super-2 number, since 2×3341311403131222 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 83532785078279 + ... + 83532785078282.
Almost surely, 2334131140313122 is an apocalyptic number.
334131140313122 is a deficient number, since it is larger than the sum of its proper divisors (167065570156564).
334131140313122 is a wasteful number, since it uses less digits than its factorization.
334131140313122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 167065570156563.
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 334131140313122 its reverse (221313041131433), we get a palindrome (555444181444555).
The spelling of 334131140313122 in words is "three hundred thirty-four trillion, one hundred thirty-one billion, one hundred forty million, three hundred thirteen thousand, one hundred twenty-two".
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