Base | Representation |
---|---|
bin | 1001101110011000110… |
… | …11010110000010011011 |
3 | 1011221110221111121001112 |
4 | 10313030123112002123 |
5 | 20433310400431021 |
6 | 413300335010535 |
7 | 33066232566032 |
oct | 4671433260233 |
9 | 1157427447045 |
10 | 334142202011 |
11 | 11978861aa82 |
12 | 54913669a4b |
13 | 25681413ac7 |
14 | 1225b759719 |
15 | 8a59c9bd5b |
hex | 4dcc6d609b |
334142202011 has 2 divisors, whose sum is σ = 334142202012. Its totient is φ = 334142202010.
The previous prime is 334142201989. The next prime is 334142202061. The reversal of 334142202011 is 110202241433.
It is a weak prime.
It is an emirp because it is prime and its reverse (110202241433) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-334142202011 is a prime.
It is a super-2 number, since 2×3341422020112 (a number of 24 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (334142202061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167071101005 + 167071101006.
It is an arithmetic number, because the mean of its divisors is an integer number (167071101006).
Almost surely, 2334142202011 is an apocalyptic number.
334142202011 is a deficient number, since it is larger than the sum of its proper divisors (1).
334142202011 is an equidigital number, since it uses as much as digits as its factorization.
334142202011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 334142202011 its reverse (110202241433), we get a palindrome (444344443444).
The spelling of 334142202011 in words is "three hundred thirty-four billion, one hundred forty-two million, two hundred two thousand, eleven".
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