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334213141312403 is a prime number
BaseRepresentation
bin100101111111101110000111…
…1100100010011001110010011
31121211100110112110022120101222
41023333130033210103032103
5322301222003133444103
63142451221511315255
7130253050126351523
oct11377341744231623
91554313473276358
10334213141312403
1197543aa7396901
12315988b497bb2b
13114642193aa152
145c76006635683
1528989b65ce638
hex12ff70f913393

334213141312403 has 2 divisors, whose sum is σ = 334213141312404. Its totient is φ = 334213141312402.

The previous prime is 334213141312331. The next prime is 334213141312429. The reversal of 334213141312403 is 304213141312433.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 334213141312403 - 212 = 334213141308307 is a prime.

It is a super-3 number, since 3×3342131413124033 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (334213143312403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167106570656201 + 167106570656202.

It is an arithmetic number, because the mean of its divisors is an integer number (167106570656202).

Almost surely, 2334213141312403 is an apocalyptic number.

334213141312403 is a deficient number, since it is larger than the sum of its proper divisors (1).

334213141312403 is an equidigital number, since it uses as much as digits as its factorization.

334213141312403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 62208, while the sum is 35.

Adding to 334213141312403 its reverse (304213141312433), we get a palindrome (638426282624836).

The spelling of 334213141312403 in words is "three hundred thirty-four trillion, two hundred thirteen billion, one hundred forty-one million, three hundred twelve thousand, four hundred three".