Base | Representation |
---|---|
bin | 100101111111101110000111… |
… | …1100100010011001110010011 |
3 | 1121211100110112110022120101222 |
4 | 1023333130033210103032103 |
5 | 322301222003133444103 |
6 | 3142451221511315255 |
7 | 130253050126351523 |
oct | 11377341744231623 |
9 | 1554313473276358 |
10 | 334213141312403 |
11 | 97543aa7396901 |
12 | 315988b497bb2b |
13 | 114642193aa152 |
14 | 5c76006635683 |
15 | 28989b65ce638 |
hex | 12ff70f913393 |
334213141312403 has 2 divisors, whose sum is σ = 334213141312404. Its totient is φ = 334213141312402.
The previous prime is 334213141312331. The next prime is 334213141312429. The reversal of 334213141312403 is 304213141312433.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 334213141312403 - 212 = 334213141308307 is a prime.
It is a super-3 number, since 3×3342131413124033 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (334213143312403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167106570656201 + 167106570656202.
It is an arithmetic number, because the mean of its divisors is an integer number (167106570656202).
Almost surely, 2334213141312403 is an apocalyptic number.
334213141312403 is a deficient number, since it is larger than the sum of its proper divisors (1).
334213141312403 is an equidigital number, since it uses as much as digits as its factorization.
334213141312403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 35.
Adding to 334213141312403 its reverse (304213141312433), we get a palindrome (638426282624836).
The spelling of 334213141312403 in words is "three hundred thirty-four trillion, two hundred thirteen billion, one hundred forty-one million, three hundred twelve thousand, four hundred three".
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