Base | Representation |
---|---|
bin | 110000101001101100111… |
… | …011101001100110111110 |
3 | 102211121200011121121101100 |
4 | 300221230323221212332 |
5 | 414234100401220132 |
6 | 11035521341553530 |
7 | 463355251143354 |
oct | 60515473514676 |
9 | 12747604547340 |
10 | 3343312132542 |
11 | 10799885a2238 |
12 | 45bb585758a6 |
13 | 1b33719807b5 |
14 | b7b6245d7d4 |
15 | 5be7958737c |
hex | 30a6cee99be |
3343312132542 has 48 divisors (see below), whose sum is σ = 7439838765840. Its totient is φ = 1084285927296.
The previous prime is 3343312132499. The next prime is 3343312132597. The reversal of 3343312132542 is 2452312133433.
3343312132542 is a `hidden beast` number, since 3 + 3 + 433 + 1 + 213 + 2 + 5 + 4 + 2 = 666.
It is a super-2 number, since 2×33433121325422 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3343312132497 and 3343312132506.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 36937113 + ... + 37027515.
It is an arithmetic number, because the mean of its divisors is an integer number (154996640955).
Almost surely, 23343312132542 is an apocalyptic number.
3343312132542 is an abundant number, since it is smaller than the sum of its proper divisors (4096526633298).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3343312132542 is a wasteful number, since it uses less digits than its factorization.
3343312132542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 145977 (or 145974 counting only the distinct ones).
The product of its digits is 155520, while the sum is 36.
Adding to 3343312132542 its reverse (2452312133433), we get a palindrome (5795624265975).
The spelling of 3343312132542 in words is "three trillion, three hundred forty-three billion, three hundred twelve million, one hundred thirty-two thousand, five hundred forty-two".
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