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3343320034 = 21671660017
BaseRepresentation
bin1100011101000111…
…0000001111100010
322122000001020212221
43013101300033202
523321342220114
61311430541254
7145564515505
oct30721601742
98560036787
103343320034
11146624290a
1279380782a
1341386c0a2
1423a05513c
151487ad524
hexc74703e2

3343320034 has 4 divisors (see below), whose sum is σ = 5014980054. Its totient is φ = 1671660016.

The previous prime is 3343319999. The next prime is 3343320077. The reversal of 3343320034 is 4300233433.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 2757825225 + 585494809 = 52515^2 + 24197^2 .

It is a super-2 number, since 2×33433200342 = 22355577699491522312, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3343319990 and 3343320008.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 835830007 + ... + 835830010.

Almost surely, 23343320034 is an apocalyptic number.

3343320034 is a deficient number, since it is larger than the sum of its proper divisors (1671660020).

3343320034 is a wasteful number, since it uses less digits than its factorization.

3343320034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1671660019.

The product of its (nonzero) digits is 7776, while the sum is 25.

The square root of 3343320034 is about 57821.4496013374. The cubic root of 3343320034 is about 1495.2919097553.

Adding to 3343320034 its reverse (4300233433), we get a palindrome (7643553467).

The spelling of 3343320034 in words is "three billion, three hundred forty-three million, three hundred twenty thousand, thirty-four".

Divisors: 1 2 1671660017 3343320034