Base | Representation |
---|---|
bin | 110000101010101111101… |
… | …001010100100111100010 |
3 | 102211201120011201100200001 |
4 | 300222233221110213202 |
5 | 414243343414321232 |
6 | 11040224403450214 |
7 | 463425061602115 |
oct | 60525751244742 |
9 | 12751504640601 |
10 | 3344431401442 |
11 | 107a40237855a |
12 | 46020b38696a |
13 | 1b34bc819ba1 |
14 | b7c2ad7657c |
15 | 5bee29776e7 |
hex | 30aafa549e2 |
3344431401442 has 4 divisors (see below), whose sum is σ = 5016647102166. Its totient is φ = 1672215700720.
The previous prime is 3344431401391. The next prime is 3344431401527. The reversal of 3344431401442 is 2441041344433.
It is a happy number.
3344431401442 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 3332965060881 + 11466340561 = 1825641^2 + 107081^2 .
It is a super-3 number, since 3×33444314014423 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 836107850359 + ... + 836107850362.
Almost surely, 23344431401442 is an apocalyptic number.
3344431401442 is a deficient number, since it is larger than the sum of its proper divisors (1672215700724).
3344431401442 is a wasteful number, since it uses less digits than its factorization.
3344431401442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1672215700723.
The product of its (nonzero) digits is 221184, while the sum is 37.
Adding to 3344431401442 its reverse (2441041344433), we get a palindrome (5785472745875).
The spelling of 3344431401442 in words is "three trillion, three hundred forty-four billion, four hundred thirty-one million, four hundred one thousand, four hundred forty-two".
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