Base | Representation |
---|---|
bin | 110000101011100011011… |
… | …010111001011101101000 |
3 | 102211210210201012112111022 |
4 | 300223203122321131220 |
5 | 414302133302113212 |
6 | 11040450513352012 |
7 | 463455440062535 |
oct | 60534332713550 |
9 | 12753721175438 |
10 | 3345300035432 |
11 | 107a808727093 |
12 | 460412268608 |
13 | 1b35ca7808b4 |
14 | b7cb0489d8c |
15 | 5c043d5a772 |
hex | 30ae36b9768 |
3345300035432 has 32 divisors (see below), whose sum is σ = 6348759691680. Its totient is φ = 1652302217280.
The previous prime is 3345300035419. The next prime is 3345300035443. The reversal of 3345300035432 is 2345300035433.
It is a super-2 number, since 2×33453000354322 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3345300035392 and 3345300035401.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5404223 + ... + 5991345.
It is an arithmetic number, because the mean of its divisors is an integer number (198398740365).
Almost surely, 23345300035432 is an apocalyptic number.
It is an amenable number.
3345300035432 is a deficient number, since it is larger than the sum of its proper divisors (3003459656248).
3345300035432 is a wasteful number, since it uses less digits than its factorization.
3345300035432 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 595793 (or 595789 counting only the distinct ones).
The product of its (nonzero) digits is 194400, while the sum is 35.
Subtracting from 3345300035432 its reverse (2345300035433), we obtain a palindrome (999999999999).
The spelling of 3345300035432 in words is "three trillion, three hundred forty-five billion, three hundred million, thirty-five thousand, four hundred thirty-two".
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