Search a number
-
+
33468125083769 is a prime number
BaseRepresentation
bin1111001110000011001111…
…01101001111100001111001
311101111112002011220020020202
413213001213231033201321
513341320210010140034
6155103013331531545
710022664224246015
oct747014755174171
9141445064806222
1033468125083769
11a733830108952
12390641b459bb5
13158a05246462c
14839c1a043545
153d08b1b2147e
hex1e7067b4f879

33468125083769 has 2 divisors, whose sum is σ = 33468125083770. Its totient is φ = 33468125083768.

The previous prime is 33468125083703. The next prime is 33468125083817. The reversal of 33468125083769 is 96738052186433.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31895521302544 + 1572603781225 = 5647612^2 + 1254035^2 .

It is a cyclic number.

It is not a de Polignac number, because 33468125083769 - 212 = 33468125079673 is a prime.

It is a super-2 number, since 2×334681250837692 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (33468125089769) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16734062541884 + 16734062541885.

It is an arithmetic number, because the mean of its divisors is an integer number (16734062541885).

It is a 1-persistent number, because it is pandigital, but 2⋅33468125083769 = 66936250167538 is not.

Almost surely, 233468125083769 is an apocalyptic number.

It is an amenable number.

33468125083769 is a deficient number, since it is larger than the sum of its proper divisors (1).

33468125083769 is an equidigital number, since it uses as much as digits as its factorization.

33468125083769 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 156764160, while the sum is 65.

The spelling of 33468125083769 in words is "thirty-three trillion, four hundred sixty-eight billion, one hundred twenty-five million, eighty-three thousand, seven hundred sixty-nine".