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3351113 is a prime number
BaseRepresentation
bin1100110010001001001001
320022020212022
430302021021
51324213423
6155454225
740325003
oct14621111
96266768
103351113
111989817
121157375
1390440c
14633373
15462dc8
hex332249

3351113 has 2 divisors, whose sum is σ = 3351114. Its totient is φ = 3351112.

The previous prime is 3351109. The next prime is 3351121. The reversal of 3351113 is 3111533.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2715904 + 635209 = 1648^2 + 797^2 .

It is a cyclic number.

It is not a de Polignac number, because 3351113 - 22 = 3351109 is a prime.

It is a super-2 number, since 2×33511132 = 22459916677538, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3351091 and 3351100.

It is not a weakly prime, because it can be changed into another prime (3351013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1675556 + 1675557.

It is an arithmetic number, because the mean of its divisors is an integer number (1675557).

Almost surely, 23351113 is an apocalyptic number.

It is an amenable number.

3351113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3351113 is an equidigital number, since it uses as much as digits as its factorization.

3351113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 135, while the sum is 17.

The square root of 3351113 is about 1830.6045449523. The cubic root of 3351113 is about 149.6452803395.

Adding to 3351113 its reverse (3111533), we get a palindrome (6462646).

The spelling of 3351113 in words is "three million, three hundred fifty-one thousand, one hundred thirteen".