Base | Representation |
---|---|
bin | 110000110100000101101… |
… | …101110100100100010011 |
3 | 102212200110110101001202112 |
4 | 300310011231310210103 |
5 | 414424421112343201 |
6 | 11045004202135535 |
7 | 464231531033105 |
oct | 60640555644423 |
9 | 12780413331675 |
10 | 3354465356051 |
11 | 1083691274127 |
12 | 46214b7b15ab |
13 | 1b442b565334 |
14 | b84dd817575 |
15 | 5c3cd7e10bb |
hex | 30d05b74913 |
3354465356051 has 2 divisors, whose sum is σ = 3354465356052. Its totient is φ = 3354465356050.
The previous prime is 3354465356023. The next prime is 3354465356111. The reversal of 3354465356051 is 1506535644533.
It is a weak prime.
It is an emirp because it is prime and its reverse (1506535644533) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3354465356051 - 230 = 3353391614227 is a prime.
It is a super-2 number, since 2×33544653560512 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3354465316051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1677232678025 + 1677232678026.
It is an arithmetic number, because the mean of its divisors is an integer number (1677232678026).
Almost surely, 23354465356051 is an apocalyptic number.
3354465356051 is a deficient number, since it is larger than the sum of its proper divisors (1).
3354465356051 is an equidigital number, since it uses as much as digits as its factorization.
3354465356051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9720000, while the sum is 50.
The spelling of 3354465356051 in words is "three trillion, three hundred fifty-four billion, four hundred sixty-five million, three hundred fifty-six thousand, fifty-one".
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