33550011133 has 4 divisors (see below), whose sum is σ = 33683676768. Its totient is φ = 33416345500.

The previous prime is 33550011031. The next prime is 33550011161. The reversal of 33550011133 is 33111005533.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33111005533 = 127 ⋅260716579.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-33550011133 is a prime.

It is a super-2 number, since 2×33550011133² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a zygodrome in base 10.

It is a junction number, because it is equal to n+sod(n) for n = 33550011098 and 33550011107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (33550011533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66832441 + ... + 66832942.

It is an arithmetic number, because the mean of its divisors is an integer number (8420919192).

Almost surely, 2^33550011133 is an apocalyptic number.

It is an amenable number.

33550011133 is a deficient number, since it is larger than the sum of its proper divisors (133665635).

33550011133 is a wasteful number, since it uses less digits than its factorization.

33550011133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 133665634.

The product of its (nonzero) digits is 2025, while the sum is 25.

Adding to 33550011133 its reverse (33111005533), we get a palindrome (66661016666).

The spelling of 33550011133 in words is "thirty-three billion, five hundred fifty million, eleven thousand, one hundred thirty-three".