Search a number
-
+
336740051 is a prime number
BaseRepresentation
bin10100000100100…
…011111011010011
3212110122011111202
4110010203323103
51142201140201
653225301415
711226146264
oct2404437323
9773564452
10336740051
1116309886a
129493486b
13549c288b
1432a1896b
151e869c6b
hex14123ed3

336740051 has 2 divisors, whose sum is σ = 336740052. Its totient is φ = 336740050.

The previous prime is 336740017. The next prime is 336740077. The reversal of 336740051 is 150047633.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-336740051 is a prime.

It is a super-2 number, since 2×3367400512 = 226787723894965202, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 336739996 and 336740023.

It is not a weakly prime, because it can be changed into another prime (336742051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 168370025 + 168370026.

It is an arithmetic number, because the mean of its divisors is an integer number (168370026).

Almost surely, 2336740051 is an apocalyptic number.

336740051 is a deficient number, since it is larger than the sum of its proper divisors (1).

336740051 is an equidigital number, since it uses as much as digits as its factorization.

336740051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7560, while the sum is 29.

The square root of 336740051 is about 18350.4782226513. The cubic root of 336740051 is about 695.7153588734.

Adding to 336740051 its reverse (150047633), we get a palindrome (486787684).

The spelling of 336740051 in words is "three hundred thirty-six million, seven hundred forty thousand, fifty-one".