Base | Representation |
---|---|
bin | 110001001100010011111… |
… | …101001100011010001011 |
3 | 102222011121001100122220001 |
4 | 301030103331030122023 |
5 | 420341202330230132 |
6 | 11104545055143431 |
7 | 466142204332321 |
oct | 61142375143213 |
9 | 12864531318801 |
10 | 3380474070667 |
11 | 10937185363a1 |
12 | 4671a9b14b77 |
13 | 1b6a14a6a4b5 |
14 | b9889b39d11 |
15 | 5ce01d16ce7 |
hex | 31313f4c68b |
3380474070667 has 2 divisors, whose sum is σ = 3380474070668. Its totient is φ = 3380474070666.
The previous prime is 3380474070643. The next prime is 3380474070683. The reversal of 3380474070667 is 7660704740833.
3380474070667 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3380474070667 - 211 = 3380474068619 is a prime.
It is a super-2 number, since 2×33804740706672 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3380474070167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1690237035333 + 1690237035334.
It is an arithmetic number, because the mean of its divisors is an integer number (1690237035334).
Almost surely, 23380474070667 is an apocalyptic number.
3380474070667 is a deficient number, since it is larger than the sum of its proper divisors (1).
3380474070667 is an equidigital number, since it uses as much as digits as its factorization.
3380474070667 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14224896, while the sum is 55.
The spelling of 3380474070667 in words is "three trillion, three hundred eighty billion, four hundred seventy-four million, seventy thousand, six hundred sixty-seven".
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