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340004013034009 is a prime number
BaseRepresentation
bin100110101001110110101101…
…0011010110100101000011001
31122120212001210021002211220211
41031103231122122310220121
5324031111204314042014
63203043404241451121
7131421323255004322
oct11523553232645031
91576761707084824
10340004013034009
119937698a520425
1232173080040aa1
13117943192057cc
145dd63d3c99449
152949440a27cc4
hex1353b5a6b4a19

340004013034009 has 2 divisors, whose sum is σ = 340004013034010. Its totient is φ = 340004013034008.

The previous prime is 340004013034001. The next prime is 340004013034013. The reversal of 340004013034009 is 900430310400043.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 337057287174400 + 2946725859609 = 18359120^2 + 1716603^2 .

It is a cyclic number.

It is not a de Polignac number, because 340004013034009 - 23 = 340004013034001 is a prime.

It is a super-2 number, since 2×3400040130340092 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (340004013034001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170002006517004 + 170002006517005.

It is an arithmetic number, because the mean of its divisors is an integer number (170002006517005).

Almost surely, 2340004013034009 is an apocalyptic number.

It is an amenable number.

340004013034009 is a deficient number, since it is larger than the sum of its proper divisors (1).

340004013034009 is an equidigital number, since it uses as much as digits as its factorization.

340004013034009 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 31.

The spelling of 340004013034009 in words is "three hundred forty trillion, four billion, thirteen million, thirty-four thousand, nine".