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3400121513102 = 21700060756551
BaseRepresentation
bin110001011110100111000…
…010001111010010001110
3110001001022022111011002012
4301132213002033102032
5421201422101404402
611121554432101222
7500436116000516
oct61364702172216
913031268434065
103400121513102
1110a0a8aa53726
1246ab71994812
131b88263a4a92
14ba7d128a846
155d6a1b41452
hex317a708f48e

3400121513102 has 4 divisors (see below), whose sum is σ = 5100182269656. Its totient is φ = 1700060756550.

The previous prime is 3400121513081. The next prime is 3400121513119. The reversal of 3400121513102 is 2013151210043.

3400121513102 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 850030378274 + ... + 850030378277.

It is an arithmetic number, because the mean of its divisors is an integer number (1275045567414).

Almost surely, 23400121513102 is an apocalyptic number.

3400121513102 is a deficient number, since it is larger than the sum of its proper divisors (1700060756554).

3400121513102 is a wasteful number, since it uses less digits than its factorization.

3400121513102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1700060756553.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 3400121513102 its reverse (2013151210043), we get a palindrome (5413272723145).

The spelling of 3400121513102 in words is "three trillion, four hundred billion, one hundred twenty-one million, five hundred thirteen thousand, one hundred two".

Divisors: 1 2 1700060756551 3400121513102