Base | Representation |
---|---|
bin | 100110101001111011010111… |
… | …1101010011010110011000011 |
3 | 1122120220000122120122222110111 |
4 | 1031103312233222122303003 |
5 | 324031242214434323301 |
6 | 3203052142423012151 |
7 | 131422126465225324 |
oct | 11523665752326303 |
9 | 1576800576588414 |
10 | 340014033120451 |
11 | 993801616046a8 |
12 | 32174bb789a057 |
13 | 11795255106841 |
14 | 5dd6aa496a44b |
15 | 294982a552551 |
hex | 1353dafa9acc3 |
340014033120451 has 2 divisors, whose sum is σ = 340014033120452. Its totient is φ = 340014033120450.
The previous prime is 340014033120409. The next prime is 340014033120469. The reversal of 340014033120451 is 154021330410043.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-340014033120451 is a prime.
It is not a weakly prime, because it can be changed into another prime (340014033120851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170007016560225 + 170007016560226.
It is an arithmetic number, because the mean of its divisors is an integer number (170007016560226).
Almost surely, 2340014033120451 is an apocalyptic number.
340014033120451 is a deficient number, since it is larger than the sum of its proper divisors (1).
340014033120451 is an equidigital number, since it uses as much as digits as its factorization.
340014033120451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 340014033120451 its reverse (154021330410043), we get a palindrome (494035363530494).
The spelling of 340014033120451 in words is "three hundred forty trillion, fourteen billion, thirty-three million, one hundred twenty thousand, four hundred fifty-one".
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