Base | Representation |
---|---|
bin | 1111011101100111100001… |
… | …10000010110000101010111 |
3 | 11110101122200120000112011221 |
4 | 13232303300300112011113 |
5 | 13424101121040222333 |
6 | 200152432424311211 |
7 | 10106431021611055 |
oct | 756636060260527 |
9 | 143348616015157 |
10 | 34003000320343 |
11 | a91a65625180a |
12 | 3992014012507 |
13 | 15c8613a01c62 |
14 | 857a7ad771d5 |
15 | 3de76938cd2d |
hex | 1eecf0c16157 |
34003000320343 has 4 divisors (see below), whose sum is σ = 34006850742528. Its totient is φ = 33999149898160.
The previous prime is 34003000320337. The next prime is 34003000320347. The reversal of 34003000320343 is 34302300030043.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34003000320343 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34003000320347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1925197846 + ... + 1925215507.
It is an arithmetic number, because the mean of its divisors is an integer number (8501712685632).
Almost surely, 234003000320343 is an apocalyptic number.
34003000320343 is a deficient number, since it is larger than the sum of its proper divisors (3850422185).
34003000320343 is an equidigital number, since it uses as much as digits as its factorization.
34003000320343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3850422184.
The product of its (nonzero) digits is 7776, while the sum is 25.
Adding to 34003000320343 its reverse (34302300030043), we get a palindrome (68305300350386).
The spelling of 34003000320343 in words is "thirty-four trillion, three billion, three hundred twenty thousand, three hundred forty-three".
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