Base | Representation |
---|---|
bin | 1001111001010110111… |
… | …11111110111111011111 |
3 | 1012111200102121120100120 |
4 | 10330223133332333133 |
5 | 21032341222034101 |
6 | 420113022330023 |
7 | 33365213122350 |
oct | 4745337767737 |
9 | 1174612546316 |
10 | 340032221151 |
11 | 121230362597 |
12 | 55a98129913 |
13 | 260ac78312c |
14 | 12659ad9d27 |
15 | 8ca1e0cb36 |
hex | 4f2b7fefdf |
340032221151 has 8 divisors (see below), whose sum is σ = 518144337024. Its totient is φ = 194304126360.
The previous prime is 340032221143. The next prime is 340032221161. The reversal of 340032221151 is 151122230043.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 340032221151 - 23 = 340032221143 is a prime.
It is a super-2 number, since 2×3400322211512 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (340032221131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8096005245 + ... + 8096005286.
It is an arithmetic number, because the mean of its divisors is an integer number (64768042128).
Almost surely, 2340032221151 is an apocalyptic number.
340032221151 is a deficient number, since it is larger than the sum of its proper divisors (178112115873).
340032221151 is a wasteful number, since it uses less digits than its factorization.
340032221151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16192010541.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 340032221151 its reverse (151122230043), we get a palindrome (491154451194).
The spelling of 340032221151 in words is "three hundred forty billion, thirty-two million, two hundred twenty-one thousand, one hundred fifty-one".
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