Base | Representation |
---|---|
bin | 1001111001010111000… |
… | …01000110101111100001 |
3 | 1012111200110011111111101 |
4 | 10330223201012233201 |
5 | 21032341310440131 |
6 | 420113032514401 |
7 | 33365215455232 |
oct | 4745341065741 |
9 | 1174613144441 |
10 | 340032515041 |
11 | 12123054337a |
12 | 55a9824ba01 |
13 | 260ac856b2b |
14 | 12659b75089 |
15 | 8ca1e69c61 |
hex | 4f2b846be1 |
340032515041 has 2 divisors, whose sum is σ = 340032515042. Its totient is φ = 340032515040.
The previous prime is 340032515003. The next prime is 340032515099. The reversal of 340032515041 is 140515230043.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 218925731025 + 121106784016 = 467895^2 + 348004^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-340032515041 is a prime.
It is a super-2 number, since 2×3400325150412 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (340032515941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170016257520 + 170016257521.
It is an arithmetic number, because the mean of its divisors is an integer number (170016257521).
Almost surely, 2340032515041 is an apocalyptic number.
It is an amenable number.
340032515041 is a deficient number, since it is larger than the sum of its proper divisors (1).
340032515041 is an equidigital number, since it uses as much as digits as its factorization.
340032515041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 340032515041 its reverse (140515230043), we get a palindrome (480547745084).
The spelling of 340032515041 in words is "three hundred forty billion, thirty-two million, five hundred fifteen thousand, forty-one".
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