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34005320257 is a prime number
BaseRepresentation
bin11111101010111000…
…000000001001000001
310020202220000020211211
4133222320000021001
51024120330222012
623342152010121
72312453311246
oct375270001101
9106686006754
1034005320257
1113470131467
126710390941
13328c12a29c
1419083855cd
15d405a06a7
hex7eae00241

34005320257 has 2 divisors, whose sum is σ = 34005320258. Its totient is φ = 34005320256.

The previous prime is 34005320249. The next prime is 34005320263. The reversal of 34005320257 is 75202350043.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30106067121 + 3899253136 = 173511^2 + 62444^2 .

It is an emirp because it is prime and its reverse (75202350043) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34005320257 - 23 = 34005320249 is a prime.

It is a super-2 number, since 2×340053202572 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (34005320267) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17002660128 + 17002660129.

It is an arithmetic number, because the mean of its divisors is an integer number (17002660129).

Almost surely, 234005320257 is an apocalyptic number.

It is an amenable number.

34005320257 is a deficient number, since it is larger than the sum of its proper divisors (1).

34005320257 is an equidigital number, since it uses as much as digits as its factorization.

34005320257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25200, while the sum is 31.

The spelling of 34005320257 in words is "thirty-four billion, five million, three hundred twenty thousand, two hundred fifty-seven".