Base | Representation |
---|---|
bin | 110001011111011011101… |
… | …010001111011101011011 |
3 | 110001010120211211012112111 |
4 | 301133123222033131123 |
5 | 421210224112233221 |
6 | 11122222211453151 |
7 | 500500026354133 |
oct | 61373352173533 |
9 | 13033524735474 |
10 | 3401004414811 |
11 | 10a13a3367863 |
12 | 46b1795b71b7 |
13 | 1b8937292a23 |
14 | ba876635ac3 |
15 | 5d7043e1be1 |
hex | 317dba8f75b |
3401004414811 has 2 divisors, whose sum is σ = 3401004414812. Its totient is φ = 3401004414810.
The previous prime is 3401004414739. The next prime is 3401004414817. The reversal of 3401004414811 is 1184144001043.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3401004414811 - 217 = 3401004283739 is a prime.
It is not a weakly prime, because it can be changed into another prime (3401004414817) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700502207405 + 1700502207406.
It is an arithmetic number, because the mean of its divisors is an integer number (1700502207406).
Almost surely, 23401004414811 is an apocalyptic number.
3401004414811 is a deficient number, since it is larger than the sum of its proper divisors (1).
3401004414811 is an equidigital number, since it uses as much as digits as its factorization.
3401004414811 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6144, while the sum is 31.
Adding to 3401004414811 its reverse (1184144001043), we get a palindrome (4585148415854).
The spelling of 3401004414811 in words is "three trillion, four hundred one billion, four million, four hundred fourteen thousand, eight hundred eleven".
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