Base | Representation |
---|---|
bin | 110001011111011101110… |
… | …110111110010000101011 |
3 | 110001010200102020111122112 |
4 | 301133131312332100223 |
5 | 421210313033303132 |
6 | 11122230010312535 |
7 | 500500655055434 |
oct | 61373566762053 |
9 | 13033612214575 |
10 | 3401041306667 |
11 | 10a14121751a4 |
12 | 46b189a2874b |
13 | 1b8941b0b924 |
14 | ba87b4ba48b |
15 | 5d70777cab2 |
hex | 317dddbe42b |
3401041306667 has 2 divisors, whose sum is σ = 3401041306668. Its totient is φ = 3401041306666.
The previous prime is 3401041306643. The next prime is 3401041306759. The reversal of 3401041306667 is 7666031401043.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3401041306667 - 210 = 3401041305643 is a prime.
It is not a weakly prime, because it can be changed into another prime (3401041300667) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700520653333 + 1700520653334.
It is an arithmetic number, because the mean of its divisors is an integer number (1700520653334).
Almost surely, 23401041306667 is an apocalyptic number.
3401041306667 is a deficient number, since it is larger than the sum of its proper divisors (1).
3401041306667 is an equidigital number, since it uses as much as digits as its factorization.
3401041306667 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 217728, while the sum is 41.
The spelling of 3401041306667 in words is "three trillion, four hundred one billion, forty-one million, three hundred six thousand, six hundred sixty-seven".
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