Base | Representation |
---|---|
bin | 1111011101110101100011… |
… | …01000111101101001101101 |
3 | 11110102101010101222201220112 |
4 | 13232322301220331221231 |
5 | 13424212032011331440 |
6 | 200200120012425405 |
7 | 10110115446423044 |
oct | 756726150755155 |
9 | 143371111881815 |
10 | 34010531355245 |
11 | a92287032a7a5 |
12 | 3993576178265 |
13 | 15c9244038023 |
14 | 85819324755b |
15 | 3dea5a600965 |
hex | 1eeeb1a3da6d |
34010531355245 has 32 divisors (see below), whose sum is σ = 43736696962560. Its totient is φ = 25297854059520.
The previous prime is 34010531355169. The next prime is 34010531355253. The reversal of 34010531355245 is 54255313501043.
It is a de Polignac number, because none of the positive numbers 2k-34010531355245 is a prime.
It is a super-2 number, since 2×340105313552452 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 122540780 + ... + 122818010.
It is an arithmetic number, because the mean of its divisors is an integer number (1366771780080).
Almost surely, 234010531355245 is an apocalyptic number.
It is an amenable number.
34010531355245 is a deficient number, since it is larger than the sum of its proper divisors (9726165607315).
34010531355245 is a wasteful number, since it uses less digits than its factorization.
34010531355245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 294725.
The product of its (nonzero) digits is 540000, while the sum is 41.
Adding to 34010531355245 its reverse (54255313501043), we get a palindrome (88265844856288).
The spelling of 34010531355245 in words is "thirty-four trillion, ten billion, five hundred thirty-one million, three hundred fifty-five thousand, two hundred forty-five".
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